let (x1,y1)=(1,4)and (x2,y2)=(−2,6) m = 6−4/-2−1 = 2/-s3 = 2/3 y=−2/3x + b ←is the partial equation to find b substitute either of the 2 given points into the partial equation using (1,4)then
4 = −2/3+ b ⇒ b = 12/3 + 2/ 3= 14/3 ⇒ y = −2/3x + 14/3 is the equation of line
