navybratrkd1
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  • 03-08-2017
  • Mathematics
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Evaluate ƒ(x) = –x 2  + 1 for x = –3.

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choco4
choco4 choco4
  • 03-08-2017
ƒ(x) = –x^2  + 1 for x = –3.

Substitute x for -3

ƒ(x) = –( -3)^ 2  + 1 
ƒ(x) = -9  + 1
ƒ(x) = -8
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